12x^2-1920x+50772=0

Solution for 12x^2-1920x+50772=0 equation:

12x^2-1920x+50772=0

a = 12; b = -1920; c = +50772;
Δ = b2-4ac
Δ = -19202-4·12·50772
Δ = 1249344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1249344}=\sqrt{5184*241}=\sqrt{5184}*\sqrt{241}=72\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1920)-72\sqrt{241}}{2*12}=\frac{1920-72\sqrt{241}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1920)+72\sqrt{241}}{2*12}=\frac{1920+72\sqrt{241}}{24}
$